Suite for arrays in C + + programming language

1-Arrays (rows and columns):

#include <iostream.h>

#include <conio.h>

void main( )

{

int b[3][3];

int i,j;

cout << "Enter numbers: \n";

for (i=0; i<3; i++)

{for (j=0; j<3; j++)

cin >> b[i][j];}

for (i=0; i<3; i++)

{for (j=0; j<3; j++)

cout << b[i][j];

cout << "\n";}

getch ();

}

2-Printing a smaller number of matrix:

#include <iostream.h>

#include <conio.h>

void main( )

{

int t[3][3],m,i,j;

cout << "Enter numbers: \n";

for (i=0; i<3; i++)

{for (j=0; j<3; j++)

cin >> t[i][j];}

m = t[0][0];

for (i=0; i<3; i++)

{for (j=0; j<3; j++)

if (m > t[i][j])

m = t[i][j];}

cout << "min= " << m;

getch ();

}

If we want to print larger number of the matrix Condition becomes if (m < t[i])

3-Program to simulate a simple calculator operations are addition, subtraction,multiplication and division where the user enter the number first then the code processand then the second number

#include <iostream.h>

#include <conio.h>

void main ( )

{

float x , y , z;

char a , oper ;

do

{

cout << "\nEnter First number,Operator,Second number: ";

cin >> x >> oper >> y ;

switch (oper)

{

case '+' : z=x+y ; break;

case '-' : z=x-y ; break;

case '*' : z=x*y ; break;

case '/' : z=x/y ; break;

default : z=0;

}

cout << "The answer is: " << z;

cout << "\nDo another (y/n)?";

cin >> a ;

}

while (a != 'n');

getch ();

}